Extract username from netgroup output

I have NO idea how portable this is, whether it would work in an environment other than my own, etc...  So - give it a try, let me know if you found some place it would not work and how you fixed it.

This is a HACK.  Someone could do this with Perl/Python/etc... and make lightwork of the problem.  That was not a possible solution for what I was trying to do.

So - I would like to automate a job to take the users who belong to a particular netgroup and apply filesystem quotas to those users.  Unfortunately, the output from a getent command is a bit difficult to simply parse.

I am going to create a file with the output of the getent command (not necessary)
[jradtke@cypher BashFoo]$ getent netgroup sysadmin > netgroup.sysadmin
sysadmin              ( , jradtke, ) ( , usern1, )  ( , dilbert, )

Remove the name of the netgroup itself from my query
[jradtke@cypher BashFoo]$ cat netgroup.sysadmin | sed 's/sysadmin//g'
              ( , jradtke, ) ( , usern1, )  ( , dilbert, )

This next step is a total hack, I replace the the trailing parenthesis ) with a newline character
[jradtke@cypher BashFoo]$ cat netgroup.sysadmin | sed 's/sysadmin//g' | sed 's/)/\n/g'
              ( , jradtke,
 ( , usern1,
  ( , dilbert,

I then display the 2nd field using the comma ',' as my Field Seperator
[jradtke@cypher BashFoo]$ cat netgroup.sysadmin | sed 's/sysadmin//g' | sed 's/)/\n/g' | awk 'BEGIN {FS=","}{print $2}'
 jradtke
 usern1
 dilbert

Lastly - I remove the leading space before each name
[jradtke@cypher BashFoo]$ cat netgroup.sysadmin | sed 's/sysadmin//g' | sed 's/)/\n/g' | awk 'BEGIN {FS=","}{print $2}' | grep -v ^$
 jradtke
 usern1
 dilbert

[jradtke@cypher BashFoo]$ cat netgroup.sysadmin | sed 's/sysadmin//g' | sed 's/)/\n/g' | awk 'BEGIN {FS=","}{print $2}' | grep -v ^$ | sed 's/\ //g'
jradtke
usern1
dilbert